数学公式1. ２次方程式の解 ax2 + bx + c = 0 ( a≠ 0 )の解は x = ( -b ± SQRT( b2 - 4ac ) ) / ( 2a ) 2. 指数(a≠0) (1) am × an = am + n (2) am ÷ an = am - n (3) ( am ) n = amn (4) ( ab ) n = anbn (5) ( a / b) n = an / bn ( b ≠ 0 ) (6) a0 = 1 (7) a-n = 1 / ( an ) (8) am/n = nSQRT( am ) ) ( a > 0 ) 3. 対数 ( a>0 , a≠1 , x>0 , y>0 ) (1) loga1 = 0 (2) logaa = 1 (3) logaxy = logax + logay (4) loga
